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2025 · Summer · Intermediate Algebra

2025 Summer · Intermediate Algebra

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Problem 1
Welcome everyone to the August edition of the ExcelAcademe Advanced Math Competition! It's been a while since I wrote one of these, so I may have forgotten some basic arithmetic :(
2+2×2+2×2×2=122 + 2 \times 2 + 2 \times 2 \times 2 = 12
You want to make the above equation true by replacing either ++'s with ×\times's or ×\times's with ++'s. Let nn be the number of replacements (not counting flip-flops like +×++ \to \times \to +) necessary to accomplish this. What is the sum of all possible nn? Answer 00 if no nn exists.
(A) 0(B) 3(C) 10(D) 15(E) 21\text{(A) } 0 \quad \text{(B) } 3 \quad \text{(C) } 10 \quad \text{(D) } 15 \quad \text{(E) } 21

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Problem 2
Okay I'm getting back into the groove here, but I'm still struggling with geometry... and I've unfortunately forgotten the value of π\pi while sketching the Jane Street logo. Fortunately, I only need to be within 1%1\% of the true value of π\pi in order to secure our Jane Street sponsorship money. I know π\pi starts with a "3.3.", so I will guess every digit past the decimal uniformly at random and hope I get close enough! If pp is the probability that I secure the sponsorship money, what is 100p\lfloor 100p \rfloor?
(A) 0(B) 2(C) 4(D) 6(E) 8\text{(A) } 0 \quad \text{(B) } 2 \quad \text{(C) } 4 \quad \text{(D) } 6 \quad \text{(E) } 8

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Problem 3
I've recently learned that number theory is quite a difficult topic. If you wish to taste Jim's Fowler, you must answer the following riddle! Joshua writes the integers from 22 to 5050, inclusive, on the chalkboard. He then chooses a positive integer nn and writes the remainder when nn is divided by each number on the chalkboard. Joshua notices that each of these remainders is nonzero and distinct from the rest! Find the sum of the smallest and largest prime factors of the smallest possible value of n+1n + 1.
(A) 40(B) 43(C) 49(D) 53(E) 54\text{(A) } 40 \quad \text{(B) } 43 \quad \text{(C) } 49 \quad \text{(D) } 53 \quad \text{(E) } 54

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Problem 4
Find the minimum value of the following over reals x,yx, y:
(x+2)2+(y+0)2  +  (x2)2+(y5)2\sqrt{(x+2)^2 + (y+0)^2} \;+\; \sqrt{(x-2)^2 + (y-5)^2}
(A) 0(B) 39(C) 41(D) 43(E) 57\text{(A) } 0 \quad \text{(B) } \sqrt{39} \quad \text{(C) } \sqrt{41} \quad \text{(D) } \sqrt{43} \quad \text{(E) } \sqrt{57}

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Problem 5
I have 33 shapes of variable size: a circle, a square, and an equilateral triangle. I assign each to either P1P_1, P2P_2, or P3P_3. I then inscribe P1P_1 in P2P_2 in some orientation, and then circumscribe P3P_3 about P2P_2 in some orientation. Out of all possible assignments of shapes to PiP_i and all possible orientations, what is the minimum\textbf{minimum} value of (R3R1)2\left(\dfrac{R_3}{R_1}\right)^2, where RiR_i is the circumradius of PiP_i?
(A) 12+3316(B) 6+338(C) 14+839(D) 6+332(E) 4\text{(A) } \tfrac{12+3\sqrt{3}}{16} \quad \text{(B) } \tfrac{6+3\sqrt{3}}{8} \quad \text{(C) } \tfrac{14+8\sqrt{3}}{9} \quad \text{(D) } \tfrac{6+3\sqrt{3}}{2} \quad \text{(E) } 4

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Problem 6
Gar-Bear slipped and dropped the xyxy-plane, causing every point (x,y)(x, y) to travel to the point (2x+3y, x+4y)(2x + 3y,\ x + 4y)! If before he slipped, Gar-Bear drew the graph of x2+4x+y210y+4=0x^2 + 4x + y^2 - 10y + 4 = 0, what is the area enclosed by the graph after the fall?
(A) 5π(B) 10π(C) 25π(D) 50π(E) 125π\text{(A) } 5\pi \quad \text{(B) } 10\pi \quad \text{(C) } 25\pi \quad \text{(D) } 50\pi \quad \text{(E) } 125\pi

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Problem 7
The above picture is the current best known solution to the n=17n = 17 case of a problem known as square packing\textit{square packing}, where the objective is to find the smallest side length of a square into which nn unit squares can be fit without overlapping. Find the minimum side length of a square into which 1010 unit squares can be fit without overlapping. (Hint: try the n=5n = 5 case first, then just add some extra squares!)
(A) 12+5(B) 22(C) 3+22(D) 10(E) 4\text{(A) } \tfrac{1}{2}+\sqrt{5} \quad \text{(B) } 2\sqrt{2} \quad \text{(C) } 3+\tfrac{\sqrt{2}}{2} \quad \text{(D) } \sqrt{10} \quad \text{(E) } 4

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Problem 8
A fourth degree polynomial P(x)P(x) with integer coefficients has roots at 1-1, 33, and 55. David couldn't find the fourth root, so he picked a random integer instead. Which of the following is not\textbf{not} a possible value of the sum of the coefficients of P(x)P(x)?
(A) 2423(B) 2827(C) 264263(D) 21282127(E) 0\text{(A) } 2^{4}-2^{3} \quad \text{(B) } 2^{8}-2^{7} \quad \text{(C) } 2^{64}-2^{63} \quad \text{(D) } 2^{128}-2^{127} \quad \text{(E) } 0

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Problem 9
Graham has 1313 crackers numbered 11 through 1313. Tintu will choose Graham's crackers at random one at a time until the sum of the numbers on her crackers is larger than the sum of the numbers on Graham's remaining crackers. How many crackers, on average, will Graham have left once this occurs?
(A) 5(B) 5.5(C) 6(D) 6.5(E) 7\text{(A) } 5 \quad \text{(B) } 5.5 \quad \text{(C) } 6 \quad \text{(D) } 6.5 \quad \text{(E) } 7

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Problem 10
Zappy picks two primes p,qp, q. He notices that there are 1212 distinct complex numbers zz satisfying both zpq1zp1=0\dfrac{z^{pq}-1}{z^{p}-1}=0 and zpq1zq1=0\dfrac{z^{pq}-1}{z^{q}-1}=0. Find the sum of the possible distinct values of pqpq.
(A) 21(B) 47(C) 57(D) 67(E) 71\text{(A) } 21 \quad \text{(B) } 47 \quad \text{(C) } 57 \quad \text{(D) } 67 \quad \text{(E) } 71

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Problem 11
Siyuan secretly swoons over sequences and series. Today he has discovered a sequence of positive real numbers {θn}n=1\{\theta_n\}_{n=1}^{\infty} subject to the following:
θn+2=θn+1+θn1θn+1θn;θ1=θ2=tan(1)\theta_{n+2} = \frac{\theta_{n+1} + \theta_n}{1 - \theta_{n+1}\theta_n}; \qquad \theta_1 = \theta_2 = \tan(1)
This sequence was too triggy for Siyuan to understand, so he made the set SS of the unique integers kik_i for which tan(ki)=θi\tan(k_i) = \theta_i, with 1i20251 \le i \le 2025. Help Siyuan by finding the number of elements of SS which are divisible by 33.

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Problem 12
Jiwu appeared in my dream last night and presented me with the following expression, but I seem to have forgotten what it evaluates to... He hinted to me that it requires the use of the identity (n+1)2=1+n(n+2)(n + 1)^2 = 1 + n(n + 2), but I'm not sure how that helps! Find the value of
1+671+681+69.\sqrt{1 + 67\sqrt{1 + 68\sqrt{1 + 69\sqrt{\cdots}}}}.

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Problem 13
There exist 20252025 positive real numbers whose sum is 20262026 and whose reciprocals sum to 20262026. If xx is one of these real numbers, then the maximum possible value of x+1xx + \dfrac{1}{x} is the simplified fraction ab\dfrac{a}{b}. Find the remainder when a+ba + b is divided by 10001000.

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Problem 14
Call an integer-coefficient polynomial PP mm-shy\textit{shy} if for any integer nn, P(n)0(modm)P(n) \equiv 0 \pmod{m}, and at least one coefficient of PP is not 0modm0 \bmod m. Find the number of 66-shy polynomials with coefficients in [0,6)[0, 6) and degree less than 55.

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Problem 15
Triangle ABC\triangle ABC has incenter II and circumcenter OO. You know that AI=AOAI = AO. What is the maximum possible value of A\angle A in degrees?

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